Dart 操作集合

final list = [ '1', '2', '3', '4', '5', '6', '7', '8', '9', '0'];

forEach

迭代集合的每一個元素

• demo

list.forEach((String it){
  print(it);
});
// 等效于
for (var it in list) {
  print(it);
}

• 輸出結果

flutter: 1
flutter: 2
flutter: 3
flutter: 4
flutter: 5
flutter: 6
flutter: 7
flutter: 8
flutter: 9
flutter: 0

where

返回一個新的、滿足條件的集合, 并且與原集合順序保持一致.

• demo

list.where((String it) {
  return int.parse(it) % 2 == 0;
}).forEach((String it) {
  print(it);
});

• 輸出結果

flutter: 2
flutter: 4
flutter: 6
flutter: 8
flutter: 0

• 優(yōu)化where((it) {}、forEach((it) {}為函數(shù)式, 直接使用鏈式調(diào)用的方式：

// 輸出結果同上
list.where((it) => int.parse(it) % 2 == 0).forEach(print);

• 或者使用自定義的方法:

list.where((it) => int.parse(it) % 2 == 0).forEach(customPrint);

void customPrint(String it) {
    it += ' - ';
    print(it);
}

• 輸出結果

flutter: 2 -
flutter: 4 -
flutter: 6 -
flutter: 8 -
flutter: 0 -

whereType

獲取指定類型的集合

var list = [1, "a", 2, "b", 3];
var ints = list.whereType<int>();

• ints

flutter: 1
flutter: 2
flutter: 3

skip

跳過, 會從指定index開始.

• demo

list.skip(3).forEach(print);

• 輸出

flutter: 4
flutter: 5
flutter: 6
flutter: 7
flutter: 8
flutter: 9
flutter: 0

take

會獲取接下來的N個值

• demo

// 跳過前三個, 接下來只取3個值
list.skip(3).take(3).forEach(print);

• 輸出

flutter: 4
flutter: 5
flutter: 6

TODO

其他方法:

• fold
• join