個(gè)人認(rèn)為微詞是個(gè)很不錯(cuò)的東西

1.自定義對(duì)象

@interface Person : NSObject

@property(nonatomic , copy)NSString * name;

@property(nonatomic , assign)int age;

@property (nonatomic , retain)NSArray * familys;

@end

2.簡(jiǎn)單實(shí)用（數(shù)據(jù)比較）

- (void)testObject1 {
    Person *person = [[Person alloc] init];
    person.name = @"gulong";
    person.age = 24;
   //整形比較
    NSPredicate * pred = [NSPredicate predicateWithFormat:@"age > 25"];
    BOOL match = [pred evaluateWithObject:person];
    NSLog(@"%s",(match)?"YES":"NO");
   //printf: NO
}

3.通配符和正則

- (void)testObject2 {
    /* 
     BEGINSWITH：檢查某個(gè)字符串是否以另一個(gè)字符串開(kāi)頭。
     ENDSWITH：檢查某個(gè)字符串是否以另一個(gè)字符串結(jié)尾。
     CONTAINS：檢查某個(gè)字符串是否以另一個(gè)字符串內(nèi)部。
     [c]不區(qū)分大小寫(xiě)[d]不區(qū)分發(fā)音符號(hào)即沒(méi)有重音符號(hào)[cd]既不區(qū)分大小寫(xiě)，又不區(qū)分發(fā)音符號(hào)。
     */
    Person *person = [[Person alloc] init];
    person.name = @"gulong";
    person.age = 24;
    
    /* 通配符 */
    NSPredicate *predicate1 = [NSPredicate predicateWithFormat:@"name LIKE[cd] '*er*'"];
         //*代表通配符Like還接受[cd].
    predicate1 = [NSPredicate predicateWithFormat:@"name LIKE[cd] '???er*'"];
    //?只匹配一個(gè)字符并且還可以接受[cd].
    //*表示有多個(gè)占位符
    /* 正則匹配 */
    NSString *regex = @"[A-Za-z]+";
    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", regex];
    
    if ([predicate evaluateWithObject:@"huang"]) {
        NSLog(@"字符串是否為純字母");
    }
    //printf 字符串是否為純字母
}

4.數(shù)組的過(guò)濾1（里面的每個(gè)對(duì)象都是字符串）

- (void)testArray1 {
    NSArray *array = [[NSArray alloc]initWithObjects:@"beijing",@"shanghai",@"guangzou",@"wuhan", nil];
    NSString *string = @"ang";
  //獲取帶有ang的所有字符串，然后形成一個(gè)數(shù)組
    NSPredicate *pred = [NSPredicate predicateWithFormat:@"SELF CONTAINS %@",string];
    NSLog(@"%@",[array filteredArrayUsingPredicate:pred]);
    //printf: shanghai,guangzou
}

5.數(shù)組的過(guò)濾2 （使用自定義的person類）

- (void)testArray2 {
    Person *person1 = [[Person alloc] init];
    person1.name = @"long";
    person1.age = 23;
    
    Person *person2 = [[Person alloc] init];
    person2.name = @"gu";
    person2.age = 23;
    
    Person *person3 = [[Person alloc] init];
    person3.name = @"long";
    person3.age = 24;

    NSArray *persons = @[person1,person2,person3];
    //直接使用對(duì)象里面的屬性就可以了，不能使用數(shù)組的某個(gè)對(duì)象名（其實(shí)format里面使用 “＝” 和 “＝＝”都是一樣可行的)
     NSPredicate *pred = [NSPredicate predicateWithFormat:@"name == 'long'"]; //相等
    NSPredicate *pred = [NSPredicate predicateWithFormat:@"name == %@",@"long"]; //相等
    NSPredicate *pred = [NSPredicate predicateWithFormat:@"age == %d",23]; //相等
    NSPredicate *pred = [NSPredicate predicateWithFormat:@"age = 23",]; //相等
    // (age > 23) AND (age < 26) AND 兩者都要滿足，OR 兩種滿足其一就可    
    // age between {23,26} 從23 到26之間 //@"name IN { 'Herbie', 'Snugs', 'Badger', 'Flap' }"; 
    //包含在其中用IN 
    NSArray *array = [persons filteredArrayUsingPredicate:pred]; 
    NSLog(@"array %@",[array description]); 
}

6.數(shù)組過(guò)濾3（對(duì)象里面還有數(shù)據(jù)）

@property (nonatomic , retain)NSArray * familys;    //person.h

- (void)testArray3 {
    Person *person1 = [[Person alloc] init];
    person1.name = @"huang";
    person1.age = 23;
    person1.familys = @[@"zhuge",@"zhangfei",@"liubei"];
    
    Person *person2 = [[Person alloc] init];
    person2.name = @"gu";
    person2.age = 23;
    person2.familys = @[@"suiquan",@"huanggai",@"lusun"];
    
    Person *person3 = [[Person alloc] init];
    person3.name = @"huang";
    person3.age = 24;
    person3.familys = @[@"caochao",@"xiahou",@"caozhi"];
    
    NSArray *persons = @[person1,person2,person3];
    /*
     * 數(shù)組包含時(shí)必須為 整個(gè)字符串，不是是部分（比如 huanggai 的 huang；這樣是無(wú)數(shù)據(jù)的）
     */
    NSPredicate *pred = [NSPredicate predicateWithFormat:@"familys CONTAINS 'huanggai'"];
    /*
     * 字符串包含時(shí)必須為 整個(gè)字符串，不是是部分（比如 huanggai 的 huang；是有用數(shù)據(jù)的）
     */
    NSPredicate *pred = [NSPredicate predicateWithFormat:@"name CONTAINS 'huanggai'"];
    NSArray *array = [persons filteredArrayUsingPredicate:pred]; NSLog(@"array %@",[array description]); //打印 person2 
}