開(kāi)發(fā)中我們調(diào)用系統(tǒng)的打電話方法，一般都是用數(shù)字電話號(hào)去調(diào)用，如果遇到號(hào)碼中包含特殊字符時(shí)直接調(diào)用撥打電話是行不通的

實(shí)驗(yàn)發(fā)現(xiàn)就算轉(zhuǎn)換UTF8編碼也是不可撥打
可用下面的三種方法對(duì)號(hào)碼字符串做處理
第一種 ：

//  特殊字符處理
NSString *commandStr = @"*#21#";
NSString *str1 = [commandStr stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLQueryAllowedCharacterSet]];

第二種 ：

NSString *commandStr = @"*#21#";
NSString *str2 = CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (CFStringRef)commandStr, (CFStringRef)@"!$&'()*+,-./:;=?@_~%#[]", NULL, kCFStringEncodingUTF8));

第三種 ：

NSString *commandStr = @"*#21#";
NSString  *reportName = [commandStr stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet characterSetWithCharactersInString:@"?!@#$^&%*+,:;='\"`<>()[]{}/\\| "].invertedSet];

再撥打就歐了

    NSMutableString *str = [[NSMutableString alloc] initWithFormat:@"telprompt://%@",str1];
    NSURL *callUrl = [NSURL URLWithString:str];
    if (@available(iOS 10.0, *)) {
        [[UIApplication sharedApplication] openURL:callUrl options:@{} completionHandler:nil];
    } else {
        // Fallback on earlier versions
        if([[UIApplication sharedApplication] canOpenURL:callUrl]){
            [[UIApplication sharedApplication] openURL:callUrl];
        }
    }

要是給您解決問(wèn)題了，來(lái)給俺點(diǎn)個(gè)贊????