Swift 獲取聯(lián)系人信息
如今很多開(kāi)發(fā)者都開(kāi)始嘗試使用Swift進(jìn)行開(kāi)發(fā),而且獲取手機(jī)通訊錄作為開(kāi)發(fā)常見(jiàn)的需求
作為一個(gè)新的開(kāi)發(fā)者,如果我們開(kāi)發(fā)的應(yīng)用需求不是特別高,只要求是iOS9以上,
那么恭喜你,基本上你寫(xiě)的很少,
你可以選擇Contacts框架,這個(gè)框架是在iOS9才出來(lái)的@available(iOS 9.0, *)
直接上代碼
首先在需要的類中
import Contacts
然后就可以使用這個(gè)框架了
首先lazy一個(gè)contactStore的對(duì)象
lazy var myContactStore: CNContactStore = {
let cn:CNContactStore = CNContactStore()
return cn
}()
首先是檢測(cè)權(quán)限,如果沒(méi)有授權(quán)就要申請(qǐng)權(quán)限,有權(quán)限則直接獲取通訊錄,沒(méi)有權(quán)限可以選擇彈窗是否需要重新開(kāi)啟權(quán)限
func checkContactStoreAuth(){
switch CNContactStore.authorizationStatus(for: .contacts) {
case .notDetermined:
print("未授權(quán)")
requestContactStoreAuthorization(myContactStore)
case .authorized:
print("已授權(quán)")
readContactsFromContactStore(myContactStore)
case .denied, .restricted:
print("無(wú)權(quán)限")
//可以選擇彈窗到系統(tǒng)設(shè)置中去開(kāi)啟
default: break
}
}
請(qǐng)求權(quán)限
func requestContactStoreAuthorization(_ contactStore:CNContactStore) {
contactStore.requestAccess(for: .contacts, completionHandler: {[weak self] (granted, error) in
if granted {
print("已授權(quán)")
self?.readContactsFromContactStore(contactStore)
}
})
}
讀取通訊錄
func readContactsFromContactStore(_ contactStore:CNContactStore) {
guard CNContactStore.authorizationStatus(for: .contacts) == .authorized else {
return
}
let keys = [CNContactFamilyNameKey,CNContactGivenNameKey,CNContactPhoneNumbersKey]
let fetch = CNContactFetchRequest(keysToFetch: keys as [CNKeyDescriptor])
do {
try contactStore.enumerateContacts(with: fetch, usingBlock: { (contact, stop) in
//姓名
let name = "\(contact.familyName)\(contact.givenName)"
print(name)
//電話
for labeledValue in contact.phoneNumbers {
let phoneNumber = (labeledValue.value as CNPhoneNumber).stringValue
print(phoneNumber)
}
})
} catch let error as NSError {
print(error)
}
}
OK 以上就是iOS9以上的獲取方式
對(duì)于iOS9以下的話就沒(méi)有那么方便了
我們只能使用iOS早期的一個(gè)AddressBook框架了
一樣的 首先import AddressBook
然后加載一個(gè)通訊錄對(duì)象
private lazy var myAddressBook: ABAddressBook = {
var error:Unmanaged<CFError>?
let ab: ABAddressBook = ABAddressBookCreateWithOptions(nil, nil).takeRetainedValue()
return ab;
}()
注意這里之所以使用lazy加載,是因?yàn)檎{(diào)用ABAddressBookCreateWithOptions進(jìn)行ABAddressBookCreateWithOptions的初始化需要設(shè)置為一個(gè)lazy變量，否則在用戶拒絕授權(quán)的情況下，程序?qū)?huì)崩潰。因?yàn)锳BAddressBookCreateWithOptions(nil, nil)得到的值為nil
所以這里一定要注意
之后也大致是同樣的方式
檢測(cè)權(quán)限
func checkAddressBookAuth() {
switch ABAddressBookGetAuthorizationStatus() {
case .notDetermined:
print("未授權(quán)")
requestAddressBookAuthorization(myAddressBook)
case .authorized:
print("已授權(quán)")
readContactsFromAddressBook(myAddressBook)
case .denied, .restricted:
print("無(wú)權(quán)限")
//可以選擇彈窗到系統(tǒng)設(shè)置中去開(kāi)啟
}
}
申請(qǐng)權(quán)限
func requestAddressBookAuthorization(_ addressBook:ABAddressBook) {
ABAddressBookRequestAccessWithCompletion(addressBook, {[weak self] (granted, error) in
if granted {
print("已授權(quán)")
self?.readContactsFromAddressBook(addressBook)
}
})
}
讀取通訊錄
func readContactsFromAddressBook(_ addressBook:ABAddressBook) {
guard ABAddressBookGetAuthorizationStatus() == .authorized else {
return
}
let allContacts = ABAddressBookCopyArrayOfAllPeople(addressBook).takeRetainedValue() as Array
for record in allContacts {
let currentContact: ABRecord = record
let name = ABRecordCopyCompositeName(currentContact).takeRetainedValue() as String
print(name)
let currentContactPhones: ABMultiValue = ABRecordCopyValue(currentContact, kABPersonPhoneProperty).takeRetainedValue() as ABMultiValue
for i in 0..<ABMultiValueGetCount(currentContactPhones){
let phoneNumber = ABMultiValueCopyValueAtIndex(currentContactPhones, i).takeRetainedValue() as! String
print(phoneNumber)
}
}
}
至于如何判斷采用哪一個(gè)框架
if #available(iOS 9.0, *) {
checkContactStoreAuth()
}else {
checkAddressBookAuth()
}
當(dāng)然,你還要這樣做
需要在info.plist中添加允許訪問(wèn)通訊錄的權(quán)限,否則iOS10以上的系統(tǒng)也會(huì)導(dǎo)致崩潰
OK 至此,通訊錄大家應(yīng)該都能夠獲取到了
這是我的模擬器運(yùn)行的結(jié)果
